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GCSE Maths Higher — Sample Paper 1

A complete GCSE Higher (grades 4–9) paper you can work on paper or on screen. Each question has its mark scheme underneath, collapsed until you want it, so you mark yourself the way an examiner would.

  • 90 minutes
  • Non-calculator
  • 40 marks · Edexcel style
  1. Question 1

    (2 marks)

    Write 0.000450.000\,45 in standard form.

    Mark scheme
    M1

    For 4.54.5 with a negative power of 10

    A1

    cao 4.5×1044.5 \times 10^{-4}

    Answer:

    4.5×1044.5 \times 10^{-4}

  2. Question 2

    (3 marks)

    Expand and simplify (x+5)(x3)(x + 5)(x - 3).

    Mark scheme
    M1

    For 3 of 4 terms correct from expansion

    M1

    For collecting 5x3x5x - 3x

    A1

    cao x2+2x15x^{2} + 2x - 15

    Answer:

    x2+2x15x^{2} + 2x - 15

  3. Question 3

    (3 marks)

    Simplify fully 6x3y29xy5\dfrac{6x^{3}y^{2}}{9xy^{5}}.

    Mark scheme
    M1

    For 69=23\frac{6}{9} = \frac{2}{3}

    M1

    For x31=x2x^{3-1} = x^{2} or y25=y3y^{2-5} = y^{-3}

    A1

    cao 2x23y3\frac{2x^{2}}{3y^{3}}

    Answer:

    2x23y3\dfrac{2x^{2}}{3y^{3}}

  4. Question 4

    (4 marks)

    Solve the simultaneous equations

    3x+2y=163x + 2y = 16

    x2y=0x - 2y = 0

    Mark scheme
    M1

    For adding the equations to eliminate yy

    A1

    x=4x = 4

    M1

    For substituting their xx into either equation

    A1

    y=2y = 2

    Answer:

    x=4x = 4, y=2y = 2

  5. Question 5

    (3 marks)

    A shop reduces the price of a coat by 20%20\% to £68. Work out the original price.

    Mark scheme
    M1

    For recognising £68 represents 80%80\%

    M1

    For 68÷0.868 \div 0.8 (or 68÷80×10068 \div 80 \times 100)

    A1

    cao £85

    Answer:

    £85

  6. Question 6

    (4 marks)

    Rationalise the denominator and simplify 63+12\dfrac{6}{\sqrt{3}} + \sqrt{12}.

    Mark scheme
    M1

    For 63×33\frac{6}{\sqrt3} \times \frac{\sqrt3}{\sqrt3}

    A1

    For 232\sqrt3

    M1

    For 12=23\sqrt{12} = 2\sqrt3

    A1

    cao 434\sqrt3

    Answer:

    434\sqrt{3}

  7. Question 7

    (4 marks)

    The nnth term of a sequence is n2+3nn^{2} + 3n.

    (a) Work out the 5th term.

    (b) Show that 40 is a term of the sequence.

    Mark scheme
    M1

    (a) For 52+3×55^{2} + 3 \times 5

    A1

    (a) cao 40

    M1

    (b) For solving n2+3n=40n^{2} + 3n = 40

    A1

    (b) For n=5n = 5 with a conclusion

    Answer:

    (a) 40 (b) n=5n = 5, so 40 is the 5th term

  8. Question 8

    (5 marks)

    A right-angled triangle has hypotenuse 13cm13\,\text{cm} and one shorter side 5cm5\,\text{cm}.

    (a) Work out the third side.

    (b) Hence work out the area of the triangle.

    Mark scheme
    M1

    (a) For 1325213^{2} - 5^{2}

    A1

    (a) cao 1212 (cm)

    M1

    (b) For 12×5×\frac12 \times 5 \times their 12

    A1

    (b) cao 3030

    B1

    (b) For correct units cm2\text{cm}^{2}

    Answer:

    (a) 12cm12\,\text{cm} (b) 30cm230\,\text{cm}^{2}

  9. Question 9

    (4 marks)

    The probability that it rains on any given day is 0.30.3, independently of other days.

    Work out the probability that it rains on exactly one of two consecutive days.

    Mark scheme
    M1

    For 0.3×0.70.3 \times 0.7

    M1

    For recognising two cases

    M1

    For 0.3×0.7+0.7×0.30.3 \times 0.7 + 0.7 \times 0.3

    A1

    cao 0.420.42

    Answer:

    0.420.42

  10. Question 10

    (4 marks)

    Prove that the sum of any three consecutive integers is always a multiple of 3.

    Mark scheme
    M1

    For defining consecutive integers as nn, n+1n+1, n+2n+2

    M1

    For summing to 3n+33n + 3

    A1

    For factorising to 3(n+1)3(n + 1)

    A1

    For a conclusion referring to a multiple of 3

    Answer:

    n+(n+1)+(n+2)=3n+3=3(n+1)n + (n+1) + (n+2) = 3n + 3 = 3(n+1), a multiple of 3

  11. Question 11

    (4 marks)

    yy is inversely proportional to x2x^{2}. When x=3x = 3, y=4y = 4.

    Work out yy when x=6x = 6.

    Mark scheme
    M1

    For y=kx2y = \frac{k}{x^{2}}

    M1

    For k=4×9=36k = 4 \times 9 = 36

    M1

    For 3636\frac{36}{36}

    A1

    cao y=1y = 1

    Answer:

    y=1y = 1

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